1/(2m^2)=1/(2m)-1/2

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Solution for 1/(2m^2)=1/(2m)-1/2 equation: 


D( m )

2*m^2 = 0

2*m = 0

2*m^2 = 0

2*m^2 = 0

2*m^2 = 0 // : 2

m^2 = 0

m = 0

2*m = 0

2*m = 0

2*m = 0 // : 2

m = 0

m in (-oo:0) U (0:+oo)

1/(2*m^2) = 1/(2*m)-(1/2) // - 1/(2*m)-(1/2)

1/(2*m^2)-(1/(2*m))+1/2 = 0

(-1/2)*m^-1+1/(2*m^2)+1/2 = 0

1/2*m^-2-1/2*m^-1+1/2 = 0

t_1 = m^-1

1/2*t_1^2-1/2*t_1^1+1/2 = 0

1/2*t_1^2-1/2*t_1+1/2 = 0

DELTA = (-1/2)^2-(1/2*1/2*4)

DELTA = -3/4

DELTA < 0

m belongs to the empty set

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